waecmaths question:
A kite on a taut string of length 50m inclined at an angle of 54o to the horizontal ground. The height of the kite above the ground is
Option A:
$50\tan {{36}^{\circ }}$
Option B:
$50\sin {{54}^{\circ }}$
Option C:
$50\tan {{54}^{\circ }}$
Option D:
$50\sin {{36}^{\circ }}$
waecmaths solution:
$h=BC=50\sin {{54}^{\circ }}$
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