waecmaths question:
If cos(x + 40o) = 0.0872, what is the value of x?
Option A:
85o
Option B:
75o
Option C:
65o
Option D:
45o
waecmaths solution:
\[\begin{align} & \cos (x+{{40}^{\circ }})=0.0872 \\ & x+{{40}^{\circ }}={{\cos }^{-1}}(0.0872) \\ & x+{{40}^{\circ }}={{84.9974}^{\circ }} \\ & x+{{40}^{\circ }}\simeq {{85}^{\circ }} \\ & x={{45}^{\circ }} \\\end{align}\]
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