waecmaths question:
The position of three ships P, Q and R at sea are illustrated in the diagram . The arrow indicated the North direction. The bearing of Q from P is 050o and $\angle PQR={{72}^{\circ }}$ .Calculate the bearing of R from Q
Option A:
130o
Option B:
158o
Option C:
222o
Option D:
252o
waecmaths solution:
\[\begin{align} & \angle PQA=\angle NPQ={{50}^{\circ }}\text{ }\!\!\{\!\!\text{ Alternate }\angle \text{s }\!\!\}\!\!\text{ } \\ & \angle AQR={{72}^{\circ }}-{{50}^{\circ }}={{22}^{\circ }} \\ & \text{The bearing of }R\text{ from }Q={{180}^{\circ }}-{{22}^{\circ }}={{158}^{\circ }} \\\end{align}\]
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