waecmaths question:
In the diagram, $PQ\parallel RS,\text{ }QU\parallel PT\text{ and }\angle PSR={{42}^{{}^\circ }}$. Find the angle x
Option A:
84o
Option B:
48o
Option C:
42o
Option D:
32o
waecmaths solution:
$\begin{align} & \angle SPQ=\angle RSP={{42}^{\circ }}\text{ }\!\!\{\!\!\text{ alternate angles }\!\!\}\!\!\text{ } \\ & \angle VQU=\angle SPQ={{42}^{\circ }}\text{ }\!\!\{\!\!\text{ corresponding angles }\!\!\}\!\!\text{ } \\\end{align}$
maths year:
maths topics: