waecmaths question:
In the figure shown, PQS is a straight line. What is the value of $\angle PRQ$
Option A:
128o
Option B:
108o
Option C:
98o
Option D:
78o
waecmaths solution:
\[\begin{align} & \angle PQR={{180}^{\circ }}-{{148}^{\circ }}={{32}^{\circ }}\text{ }\!\!\{\!\!\text{ sum of }\angle \text{s on a straight line }\!\!\}\!\!\text{ } \\ & \angle PRQ={{180}^{\circ }}-(\angle PQR+\angle QPR)={{180}^{\circ }}-({{70}^{\circ }}+{{32}^{\circ }})={{78}^{\circ }} \\ & \\\end{align}\]
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