$\begin{align}  & \text{Using sine rule} \\ & \sin A=\frac{a\sin C}{c}=\frac{651\times \sin {{73}^{\circ }}22'}{792}=0.7876 \\ & A={{\sin }^{-1}}0.7876={{51}^{\circ }}58' \\ & B={{180}^{\circ }}-(A+C)={{180}^{\circ }}-({{73}^{\circ }}22'+{{51}^{\circ }}58) \\ & B={{54}^{\circ }}{{40}^{'}} \\ & b=\frac{c\sin B}{\sin C}=\frac{792\times \sin {{54}^{\circ }}{{40}^{'}}}{\sin {{73}^{\circ }}22'}=674.33 \\\end{align}$