Maths Question:
$\text{ Where possible solve the triangle }c=4.13,\text{ }b=5.62,\text{ }C={{61}^{\circ }}23'$
Maths Solution:
$\begin{align} & \text{Using sine rule }\frac{b}{\sin B}=\frac{c}{\sin C} \\ & \sin B=\frac{b\sin C}{c}=\frac{5.62\times \sin {{61}^{\circ }}23'}{4.13}=1.194 \\ & \text{It is impossible, since sin}\theta \text{ ranges from }-1\text{ to }1 \\\end{align}$
University mathstopic: