If ${{27}^{x}}={{9}^{y}}$ find the value of $\tfrac{x}{y}$

Solve ${{\left( \frac{27}{125} \right)}^{-\tfrac{1}{3}}}\times {{\left( \frac{4}{9} \right)}^{\tfrac{1}{2}}}$

Simplify $\sqrt{\frac{{{8}^{2}}\times {{4}^{n+1}}}{{{2}^{2n}}\times 16}}$

If ${{9}^{(2-x)}}=3$, find x

Multiply $2.7\times {{10}^{-4}}$ by $6.3\times {{10}^{6}}$ and leave your answer in standard form