waecmaths question:
If ${{9}^{(2-x)}}=3$, find x
Option A:
1
Option B:
$\tfrac{3}{2}$
Option C:
2
Option D:
$\tfrac{5}{2}$
waecmaths solution:
$\begin{align} & {{9}^{(2-x)}}=3 \\ & {{3}^{2(2-x)}}={{3}^{1}} \\ & 2(2-x)=1 \\ & 4-2x=1 \\ & 2x=3 \\ & x=\frac{3}{2} \end{align}$
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