The shaded area that gives the solution set for the inequalities $x+y\le 3,x-y\le 3$, is

Solve the quadratic inequality ${{x}^{2}}-5x+6\ge 0$

Find the range of value of x which satisfy the inequality $4x-7\le 3x\text{ and }3x-4\le 4x$

The solution of the quadratic inequality is $({{x}^{2}}+x-12)\ge 0$is

If $y={{x}^{2}}-x-12,$find the range of x for which y ≥ 0

Solve the inequality for which $\frac{x+4}{3}-\frac{x-3}{2}<4$

The solution set of the shaded area is

Find the range of value of x for which  $7x-3>25+3x$

The shaded area in the diagram above is represented by

What are the integral values of x which satisfy the inequality $-1<3-2x\le 5$