waecmaths question:
P naira invested for 4 years at r % simple interest per annum yield 0.36P naira interest. Find the value of r
Option A:
$1\tfrac{1}{9}$
Option B:
$1\tfrac{4}{9}$
Option C:
9
Option D:
11
waecmaths solution:
$R=\frac{100\times I}{P\times T}=\frac{100\times 0.36P}{P\times 4}=9$
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