waecmaths question:
Simplify $\sqrt{50}+\frac{10}{\sqrt{2}}$
Option A:
10
Option B:
$10\sqrt{2}$
Option C:
20
Option D:
$20\sqrt{2}$
waecmaths solution:
$\begin{align} & \sqrt{50}+\frac{10}{\sqrt{2}}=\frac{\sqrt{100}+10}{\sqrt{2}}=\frac{10+10}{\sqrt{2}} \\ & =\frac{20}{\sqrt{2}}=\frac{20}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=\frac{20\sqrt{2}}{2}=10\sqrt{2} \\\end{align}$
maths year: