Jambmaths question:
|
Numbers |
1 |
2 |
3 |
4 |
5 |
6 |
|
Frequency |
18 |
22 |
20 |
16 |
10 |
14 |
The table above represent the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4
Option A:
$\tfrac{1}{2}$
Option B:
$\tfrac{2}{5}$
Option C:
$\tfrac{3}{4}$
Option D:
$\tfrac{1}{5}$
Jamb Maths Solution:
$\begin{align} & \text{Total possible outcomes }=100 \\ & \text{Expected outcomes of least 4 }=16+10+14=40 \\ & \text{probabililty }=\frac{40}{100}=\frac{2}{5} \\\end{align}$
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