Jambmaths question:
In how many ways can a team of 3 girls be selected from 7 girls?
Option A:
$\tfrac{7!}{4!}$
Option B:
$\tfrac{7!}{3!4!}$
Option C:
$\tfrac{7!}{2!5!}$
Option D:
$\tfrac{7!}{3!}$
Jamb Maths Solution:
$\text{The possible selection is}{{\text{ }}^{7}}{{C}_{3}}=\frac{7!}{3!4!}$
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