waecmaths question:
PQRS is a trapezium. $QR\parallel PS,\text{ }\left| QR \right|=6cm,\text{ }\left| PS \right|=10cm\text{ and }\angle QPS={{42}^{\circ }}$
Calculate; correct to the nearest cm2 the area of the trapezium
Option A:
27cm2
Option B:
30cm2
Option C:
36cm2
Option D:
37cm2
waecmaths solution:
$\begin{align} & A=\tfrac{1}{2}(a+b)h=\tfrac{1}{2}(6+10)3.35c{{m}^{2}}=26.8c{{m}^{2}} \\ & A\approx 27cm\text{ (to the nearest c}{{\text{m}}^{2}}) \\\end{align}$
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