waecmaths question:
PQRS is a trapezium. $QR\parallel PS,\text{ }\left| QR \right|=6cm,\text{ }\left| PS \right|=10cm\text{ and }\angle QPS={{42}^{\circ }}$
Calculate the perpendicular distance between the parallel between the parallel sides
Option A:
3.35 cm
Option B:
3.72 cm
Option C:
4.50 cm
Option D:
4.62 cm
waecmaths solution:
$\begin{align} & AQ=5cm\sin {{42}^{\circ }} \\ & AQ=3.346cm \\ & AQ\approx 3.35cm \\\end{align}$
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