Jambmaths question:
A student sitting on a tower 68 metres high observes his principal car at an angle of depression of 20o. How far is the car from the bottom of the tower to the nearest metres?
Option A:
184m
Option B:
185m
Option C:
186m
Option D:
187m
Jamb Maths Solution:
$\begin{align} & \angle ABC=\angle BCD\text{ (Alternate angle)} \\ & \text{tan2}{{\text{0}}^{\text{o}}}=\frac{68}{x} \\ & x=\frac{68}{\tan {{20}^{\text{o}}}}\approx 187m \\\end{align}$
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