waecmaths question:
A ship sails x km due east to a point E and continues x km due north to F . Find the bearing of F from the starting point.
Option A:
045o
Option B:
090o
Option C:
135o
Option D:
225o
waecmaths solution:
$\begin{align} & \tan \theta =\frac{opp}{adj}=\frac{x}{x}=1 \\ & \theta ={{\tan }^{-1}}(1)={{45}^{\circ }} \\ & \angle NCF={{90}^{\circ }}-{{45}^{\circ }}={{45}^{\circ }} \\ & \text{The bearing of }F\text{ from the start point is 04}{{\text{5}}^{\circ }} \\\end{align}$
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