waecmaths question:
Simplify $\frac{x-4}{4}-\frac{x-3}{6}$
Option A:
$\frac{x-18}{12}$
Option B:
$\frac{x-6}{12}$
Option C:
$\frac{x-18}{24}$
Option D:
$\frac{x-6}{24}$
waecmaths solution:
$\begin{align} & \frac{x-4}{4}-\frac{x-3}{6}=\frac{3(x-4)-2(x-3)}{12} \\ & \frac{x-4}{4}-\frac{x-3}{6}=\frac{3x-12-2x+6}{12} \\ & \frac{x-4}{4}-\frac{x-3}{6}=\frac{x-6}{12} \\\end{align}$
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