waecmaths question:
Each of the interior angle of a regular polygon is 140o. Calculate the sum of all the interior angles of the polygon
Option A:
1080o
Option B:
1260o
Option C:
1800o
Option D:
2160o
waecmaths solution:
The sum of the interior angle and the exterior angle of any polygon is 180
Therefore, each exterior angle will be 180o – 140o = 40o
The total sum of exterior angles of any polygon is 360o
Therefore 40on =360o {n = number of sides}
n = 9
The total interior angle is given by (n – 2)180o = (9 – 2)180o =1260o
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