waecmaths question:
If $\log 2=x,\log 3=y\text{ and }\log 7=z$ find, in term of x, y and z. The value of $\log (\tfrac{28}{3})$
Option A:
$2x+y=z$
Option B:
$2x+z-y$
Option C:
$x+y-2z$
Option D:
$x+z-y$
waecmaths solution:
$\begin{align} & \log \left( \frac{28}{3} \right)=\log (4\times 7)-\log 3 \\ & =\log 4+log7-log3 \\ & =log{{2}^{2}}+\log 7-log3 \\ & =2\log 2+\log 7-\log 3 \\ & =2x+z-y \end{align}$
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