waecmaths question: Solve the equation ${{x}^{2}}+5x+6=0$ waecmaths solution: $\begin{align} & {{x}^{2}}+5x+6=0 \\ & (x+3)(x+2)=0 \\ & x=-3\text{ }or\text{ }x=-2 \\ \end{align}$ maths year: WAEC MAY/JUNE 2019
