waecmaths question:
If $\tan x=\frac{3}{4}$, $0{}^\circ <x<90{}^\circ $evaluate $\frac{\cos x}{2\sin x}$
Option A:
$\frac{8}{3}$
Option B:
$\frac{3}{2}$
Option C:
$\frac{4}{3}$
Option D:
$\frac{2}{3}$
waecmaths solution:
$\begin{align} & \tan x=\frac{3}{4} \\ & \frac{\sin x}{\cos x}=\frac{3}{4} \\ & \frac{\cos x}{\sin x}=\frac{4}{3} \\ & \frac{\cos x}{2\sin x}=\frac{4}{2(3)}=\frac{2}{3} \\\end{align}$
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