waecmaths question:
If m : n = 2 : 1, evaluate $\frac{3{{m}^{2}}-2{{n}^{2}}}{{{m}^{2}}+mn}$
Option A:
$\frac{4}{3}$
Option B:
$\frac{5}{2}$
Option C:
$\frac{3}{4}$
Option D:
$\frac{3}{5}$
waecmaths solution:
$\frac{3{{m}^{2}}-2{{n}^{2}}}{{{m}^{2}}+mn}=\frac{3{{(2)}^{2}}-2{{(1)}^{2}}}{{{2}^{2}}+2\cdot 1}=\frac{12-2}{4+2}=\frac{10}{6}=\frac{5}{3}$
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