Maths Question:
Solve the equation ${{\log }_{10}}({{x}^{2}}+9)-2{{\log }_{10}}x=1$
Maths Solution:
$\begin{align} & {{\log }_{10}}({{x}^{2}}+9)-2{{\log }_{10}}x=1 \\ & {{\log }_{10}}({{x}^{2}}+9)-{{\log }_{10}}{{x}^{2}}=1 \\ & {{\log }_{10}}\frac{{{x}^{2}}+9}{{{x}^{2}}}={{\log }_{10}}10 \\ & \frac{{{x}^{2}}+9}{{{x}^{2}}}=10 \\ & {{x}^{2}}+9=10{{x}^{2}} \\ & 9{{x}^{2}}-9=0 \\ & {{(3x)}^{2}}-{{3}^{2}}=0 \\ & (3x-3)(3x+3)=0 \\ & x=1\text{ or }x=-1 \\ \end{align}$
University mathstopic:
