Maths Question:
Solve the equation ${{\log }_{2}}({{x}^{2}}-5x-10)=2$
Maths Solution:
$\begin{align} & {{\log }_{2}}({{x}^{2}}-5x-10)=2 \\ & {{x}^{2}}-5x-10=4 \\ & {{x}^{2}}-5x-14=0 \\ & (x-7)(x+2)=0 \\ & x=7\text{ or }x=-2 \\\end{align}$
University mathstopic: