Maths Question:
$\text{Establish }(\tan \theta +\cot \theta )\tan \theta ={{\sec }^{2}}\theta $
Maths Solution:
$\begin{align} & (\tan \theta +\cot \theta )\tan \theta =\left( \frac{\sin \theta }{\cos \theta }+\frac{\cos \theta }{\sin \theta } \right)\frac{\sin \theta }{\cos \theta } \\ & (\tan \theta +\cot \theta )\tan \theta =\left( \frac{{{\sin }^{2}}\theta +{{\cos }^{2}}\theta }{\sin \theta \cos \theta } \right)\times \frac{\sin \theta }{\cos \theta }\left| {{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1 \right. \\ & (\tan \theta +\cot \theta )\tan \theta =\left( \frac{1}{\cos \theta } \right)\times \frac{1}{\cos \theta } \\ & (\tan \theta +\cot \theta )\tan \theta =\frac{1}{{{\cos }^{2}}\theta }={{\sec }^{2}}\theta \\\end{align}$
University mathstopic:
