waecmaths question:
Calculate the mean deviation of 5, 3, 0, 7, 2, 1
Option A:
0.0
Option B:
2.0
Option C:
2.5
Option D:
3.0
waecmaths solution:
$\begin{align} & mean=\frac{5+3+0+7+2+1}{6}=\frac{18}{6}=3 \\ & mean\text{ }deviation=\frac{\left| 5-3 \right|+\left| 3-3 \right|+\left| 0-3 \right|+\left| 7-3 \right|+\left| 2-3 \right|+\left| 1-3 \right|}{6} \\ & mean\text{ }deviation=\frac{2+0+3+4+1+2}{6}=\frac{12}{6}=2 \\\end{align}$
maths year:
maths topics: