waecmaths question:
Simplify $\frac{3x-y}{xy}-\frac{2x+3y}{2xy}+\frac{1}{2}$
Option A:
$\frac{4x+5y-xy}{2xy}$
Option B:
$\frac{5y-4x+xy}{2xy}$
Option C:
$\frac{5x+4y-xy}{2xy}$
Option D:
$\frac{4x-5y+xy}{2xy}$
waecmaths solution:
$\begin{align} & \frac{3x-y}{xy}-\frac{2x+3y}{2xy}+\frac{1}{2}=\frac{2(3x-y)-(2x+3y)+xy}{2xy} \\ & \frac{3x-y}{xy}-\frac{2x+3y}{2xy}+\frac{1}{2}=\frac{6x-2y-2x-3y+xy}{2xy} \\ & \frac{3x-y}{xy}-\frac{2x+3y}{2xy}+\frac{1}{2}=\frac{4x-5y+xy}{2xy} \\\end{align}$
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