Make p the subject of relation: $q=\frac{3p}{r}+\frac{s}{2}$

Make u the subject of the formula, $E=\frac{m}{2g}({{v}^{2}}-{{u}^{2}})$

Given that ${{p}^{\tfrac{1}{3}}}=\frac{\sqrt[3]{q}}{r}$, make q the subject of the equation