Question 19
The 4th term of an AP is 13 while the 10th term is 31. Find the 24th term
The 4th term of an AP is 13 while the 10th term is 31. Find the 24th term
$\begin{align} & \text{The }nth\text{ term of the progression }\tfrac{4}{2},\tfrac{7}{3},\tfrac{10}{4},\tfrac{13}{4},\cdot \cdot \cdot \text{ is} \\ & (A)\text{ }\tfrac{3n-1}{n+1}\text{ }(B)\text{ }\tfrac{1-3n}{n+1}\text{ }(C)\text{ }\tfrac{3n+1}{n+1}\text{ (D) }\tfrac{3n+1}{n-1} \\\end{align}$
$\begin{align} & \text{If the sum of the first term of G}\text{.P is 3, and the sum of the second and} \\ & \text{the third term is }-6,\text{ find the sum of the first term and the common ratio} \\ & \text{(A) 5 (B) }-2\text{ (C) }-3\text{ }(D)\text{ }-5 \\\end{align}$
The sum to infinity of a geometric progression is $-\tfrac{1}{10}$and the first term is $-\tfrac{1}{8}$.Find the common ratio of the progression.
The nth term of a sequence ${{n}^{2}}-6n-4$. Find the sum of the 3rd and 4th terms.
The second term of a geometric series is 4, while the fourth term is 16. Find the sum of the first five terms
Find the sum of the first 18 terms of the series 3, 6, 9, -, -, -, 36.
The 3rd term of an arithmetic progression is – 9 and the 7th term is –29. Find the 10th term of the progression
Find the sum to infinity 0.5 + 0.05 + 0.005 +0.0005 +….
Find to infinity, the sum of the sequence $1,\tfrac{9}{10},{{(\tfrac{9}{10})}^{2}},{{(\tfrac{9}{10})}^{3}}\cdot \cdot \cdot $
