waecmaths question:
Simplify $\frac{\tfrac{1}{x}+\tfrac{1}{y}}{x+y}$
Option A:
$\frac{1}{x+y}$
Option B:
$\frac{1}{xy}$
Option C:
$x+y$
Option D:
xy
waecmaths solution:
$\frac{\tfrac{1}{x}+\tfrac{1}{y}}{x+y}=\frac{\tfrac{x+y}{xy}}{x+y}=\frac{x+y}{xy(x+y)}=\frac{1}{xy}$
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