waecmaths question:
Find the equation whose roots are ¾ and –4
Option A:
$4{{x}^{2}}-13x+12=0$
Option B:
$4{{x}^{2}}-13x-12=0$
Option C:
$4{{x}^{2}}+13x+12=0$
Option D:
$4{{x}^{2}}+13x+12=0$
waecmaths solution:
$\begin{align} & (x-\tfrac{3}{4})(x+4)=0 \\ & {{x}^{2}}+4x-\tfrac{3}{4}x-3=0 \\ & 4{{x}^{2}}+16x-3x-12=0 \\ & 4{{x}^{2}}+13x-12=0 \\\end{align}$
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