waecmaths question:
Simplify $\frac{54{{k}^{2}}-6}{3k+1}$
Option A:
$6(1-3{{k}^{2}})$
Option B:
$6(3{{k}^{2}}-1)$
Option C:
$6(3k-1)$
Option D:
$6(1-3k)$
waecmaths solution:
$\begin{align} & \frac{54{{k}^{2}}-6}{3k+1}=\frac{6(9{{k}^{2}}-1)}{(3k+1)} \\ & =\frac{6(3k-1)(3k+1)}{(3k+1)} \\ & =6(3k-1) \end{align}$
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