waecmaths question:
Simplify $\frac{{{x}^{2}}-{{y}^{2}}}{{{(x+y)}^{2}}}\div \frac{{{(x-y)}^{2}}}{(3x+3y)}$
Option A:
$\frac{x-y}{2}$
Option B:
x + y
Option C:
$\frac{3}{x-y}$
Option D:
x – y
waecmaths solution:
$\begin{align} & \frac{{{x}^{2}}-{{y}^{2}}}{{{(x+y)}^{2}}}\div \frac{{{(x-y)}^{2}}}{(3x+3y)}=\frac{(x-y)(x+y)}{{{(x+y)}^{2}}}\times \frac{3(x+y)}{{{(x-y)}^{2}}} \\ & =\frac{3}{(x-y)} \end{align}$
maths year:
maths topics: