Maths Question:
Simplify as much as possible $\frac{1}{\sqrt{x+1}-\sqrt{x-1}}$
Maths Solution:
$\begin{align} & \frac{1}{\sqrt{x+1}-\sqrt{x-1}}=~\frac{1}{\sqrt{x+1}-\sqrt{x-1}}\times \frac{\sqrt{x+1}+\sqrt{x-1}}{\sqrt{x+1}+\sqrt{x-1}} \\ & \frac{1}{\sqrt{x+1}-\sqrt{x-1}}=\frac{\sqrt{x+1}+\sqrt{x-1}}{(x+1)-(x-1)} \\ & \frac{1}{\sqrt{x+1}-\sqrt{x-1}}=\frac{\sqrt{x+1}+\sqrt{x-1}}{2} \\\end{align}$
University mathstopic: