waecmaths question:
One of the factors of $(mn-nq-{{n}^{2}}+mq)$ is (m – n). The other factor is
Option A:
(m – q)
Option B:
(q – n)
Option C:
(n + q)
Option D:
(q – m)
waecmaths solution:
$\begin{align} & mn-nq-{{n}^{2}}+mq=mn-{{n}^{2}}+mq-nq \\ & =n(m-n)+q(m-n) \\ & =(n+q)(m-n) \end{align}$The other factor (n + q)
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