Jambmaths question:
If ${{\log }_{10}}2=0.3010\text{ and }{{\log }_{10}}7=0.8451$ evaluate ${{\log }_{10}}280$
Jamb Maths Solution:
$\begin{align} & {{\log }_{10}}280={{\log }_{10}}(4\times 7\times 10)={{\log }_{10}}4+{{\log }_{10}}7+{{\log }_{10}}10 \\ & {{\log }_{10}}280={{\log }_{10}}{{2}^{2}}+{{\log }_{10}}7+1 \\ & {{\log }_{10}}280=2{{\log }_{10}}2+{{\log }_{10}}7+1 \\ & {{\log }_{10}}280=2(0.3010)+0.8451+1=0.6020+0.8451+1 \\ & {{\log }_{10}}280=2.4471 \\\end{align}$
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