waecmaths question:
A fair coin is tossed three times. Find the probability of getting two head and one tail
Option A:
$\tfrac{1}{2}$
Option B:
$\tfrac{3}{8}$
Option C:
$\tfrac{1}{4}$
Option D:
$\tfrac{1}{8}$
waecmaths solution:
$\begin{align} & \Pr (H)=\tfrac{1}{2} \\ & \Pr (T)=\tfrac{1}{2} \\ & \Pr (HHT)=\tfrac{1}{2}\times \tfrac{1}{2}\times \tfrac{1}{2}=\tfrac{1}{8} \\\end{align}$
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