waecmaths question:
Simplify $\frac{3{{x}^{3}}}{{{(3x)}^{3}}}$
Option A:
1
Option B:
$\tfrac{1}{3}$
Option C:
$\tfrac{1}{9}$
Option D:
$\tfrac{1}{27}$
waecmaths solution:
$\frac{3{{x}^{3}}}{{{(3x)}^{3}}}=\frac{3{{x}^{3}}}{27{{x}^{3}}}=\frac{1}{9}$
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