waecmaths question:
If 2x = y, find ${{2}^{(2+\tfrac{x}{3})}}$
Option A:
$4{{y}^{\tfrac{1}{3}}}$
Option B:
$4{{y}^{-3}}$
Option C:
$2{{y}^{\tfrac{1}{3}}}$
Option D:
$2{{y}^{-3}}$
waecmaths solution:
${{2}^{(2+\tfrac{x}{3})}}={{2}^{2}}\times {{2}^{\tfrac{x}{3}}}=4({{2}^{x}}\times {{2}^{\tfrac{1}{3}}})=4(y\times \tfrac{1}{8})=\tfrac{y}{2}$
maths year:
maths topics: