Maths Question:
$\text{Show that }(a+b)(b+c)(a+c)\ge 8abc$
Maths Solution:
$\begin{align} & a+b\ge 2\sqrt{ab} \\ & a+c\ge 2\sqrt{ac} \\ & b+c\ge 2\sqrt{bc} \\ & \therefore (a+b)(b+c)(a+c)\ge 2\sqrt{ab}\times 2\sqrt{ac}\times 2\sqrt{bc} \\ & (a+b)(b+c)(a+c)\ge 8abc \\\end{align}$
University mathstopic: