Jambmaths question:
Find the sum of the first 10 terms of the A.P, 3+10+17+….
Option A:
345
Option B:
415
Option C:
321
Option D:
315
Jamb Maths Solution:
$\begin{align} & a=3,\text{ }d=10-3=7 \\ & {{S}_{n}}=\tfrac{n}{2}[2a+(n-1)d] \\ & {{S}_{10}}=\frac{10}{2}[2\times 3+(10-1)7]=5[6+63] \\ & {{S}_{10}}=345 \\\end{align}$
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