waecmaths question:
Factorize completely $32{{x}^{2}}y-48{{x}^{3}}{{y}^{3}}$
Option A:
$16{{x}^{2}}y(2-3x{{y}^{2}})$
Option B:
$8xy(4x-6{{x}^{2}}{{y}^{2}})$
Option C:
$8{{x}^{2}}y(4-6x{{y}^{2}})$
Option D:
$16xy(2x-3{{x}^{2}}{{y}^{2}})$
waecmaths solution:
$32{{x}^{2}}y-48{{x}^{3}}{{y}^{3}}=16{{x}^{2}}y(2-3x{{y}^{2}})$
maths year:
maths topics: