waecmaths question:
Find the equation whose roots are 2 and $-3\tfrac{1}{2}$
Option A:
$2{{x}^{2}}+3x+14$
Option B:
$2{{x}^{2}}+5x+7=0$
Option C:
$2{{x}^{2}}+5x-7=0$
Option D:
$2{{x}^{2}}+3x-14=0$
waecmaths solution:
$\begin{align} & (x-2)(x+3\tfrac{1}{2})=0 \\ & (x-2)(x+\tfrac{7}{2})=0 \\ & {{x}^{2}}+\tfrac{7x}{2}-2x-7=0 \\ & {{x}^{2}}+\tfrac{3x}{2}-7=0 \\ & 2{{x}^{2}}+3x-14=0 \\\end{align}$
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