Jambmaths question:
If $\frac{dy}{dx}=x+\cos x$ find y
Option A:
$\tfrac{{{x}^{2}}}{2}-\sin x+c$
Option B:
${{x}^{2}}-\sin x+c$
Option C:
$\tfrac{{{x}^{2}}}{2}+\sin x+c$
Option D:
${{x}^{2}}+\sin x+c$
Jamb Maths Solution:
$\begin{align} & \frac{dy}{dx}=x+\cos x \\ & y=\int{(x+\cos x)dx} \\ & y=\tfrac{{{x}^{2}}}{2}+\sin x+c \\\end{align}$
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