waecmaths question:
In the diagram$PQ\parallel TS,PR\parallel TU$ reflex angle QPS =245o, $\angle PST={{115}^{{}^\circ }},\angle STU={{65}^{{}^\circ }}$ and $\angle RPS=x$. Find the value of x
Option A:
80o
Option B:
70o
Option C:
60o
Option D:
50o
waecmaths solution:
$\angle SPQ=\angle PST={{115}^{{}^\circ }}\text{ }\!\!~\!\!\text{ }\!\!~\!\!\text{ }\{\text{ alternate angles }$
$\angle QPR=\angle STU={{65}^{{}^\circ }}\text{ }\!\!~\!\!\text{ }\{\text{ corresponding angles }\}\text{ }$
$x=\angle RPS=\angle SPQ-\angle QPR$
$x={{115}^{{}^\circ }}-{{65}^{{}^\circ }}={{50}^{{}^\circ }}$
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