Jambmaths question:
In how many ways can a delegates of 3 be chosen 5men and 3woman, if at least 1man and 1 woman must be included?
Jamb Maths Solution:
\[\begin{align} & MenWoman\text{ combination value} \\ & 21\text{ }{{\text{ }}^{5}}{{C}_{2}}{{\times }^{3}}{{C}_{1}}=10\times 3=30 \\ & 12\text{ }{{\text{ }}^{5}}{{C}_{1}}{{\times }^{3}}{{C}_{2}}=5\times 3=15 \\ & \text{Total}=30+15=45ways \\\end{align}\]
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