Jambmaths question:
In how many ways can the letters of the word ACCEPTANCE be arranged?
Option A:
$\tfrac{10!}{2!2!3!}$
Option B:
$\tfrac{10!}{2!3!}$
Option C:
$\tfrac{10!}{2!2!}$
Option D:
$10!$
Jamb Maths Solution:
$\begin{align} & ACCEPTANCE \\ & No\text{ }of\text{ }C=3 \\ & No\text{ }of\text{ }A=2 \\ & No\text{ }of\text{ }E=2 \\ & Acceptance\text{ }has\text{ }10\text{ }letters \\ & Possible\text{ }arrangement\text{ }=\frac{10!}{2!2!3!} \\\end{align}$
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