waecmaths question:
Each exterior angle of a polygon is 30o. Calculate the sum of the interior angles
Option A:
540o
Option B:
720o
Option C:
1080o
Option D:
1800o
waecmaths solution:
$\begin{align} & \text{The total exterior angles in }n-sided\text{ polygon is given as }{{360}^{\circ }} \\ & {{30}^{\circ }}n={{360}^{\circ }} \\ & n=12 \\ & \text{For interior angles , the sum is given by } \\ & (n-2)\times {{180}^{\circ }}=(12-2)\times {{180}^{\circ }}={{1800}^{\circ }} \\\end{align}$
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